Calculus - Fanyu Zhao

Key Points

1. Functions Definition

1.1 Each x has only one y

A function denoted f(x) of a single variable x is a rule that assigns each element of a set X ( written xX ) to exactly one element y of a set Y ( yY) :

y=f(x)orxf(x)
1.2 Domain of f

Domf Domain of Function

Imf Image of Function

For a given value of x, there should be at most one value of y.

1.3 Implicit Form f(x,y)=0

For example,

4y42y2x2yx2+x2+3=0
1.4 Polynomials
y=f(x)=a0+a1x+a2x2+...+anxn

2. Implicit Differentiation

For example,

y=ax

Mainly two ways to take derivatives,

ln(y)=ln(ax)=xln(a)1ydydx=ln(a)by taking derivatives to xdydx=yln(a)

and plug y=ax inside

dydx=axln(a)

Or, simply we apply the exponential transformation, and take deriviatives later.

y=eln(ax)=exln(a)

However, for a polynomial, we normally have to do the implicit differentiation.

4y42y2x2yx2+x2+3=016y3y(4yyx2+4y2x)(yx2+2yx)+2x=0(16y32yx2x2)y=2x+4y2x+2xyy=2x+4y2x+2xy16y32yx2x2

3. L 'Hospital's Rule & Limitations

If there is a limitation (, which is called as the inderterminate form),

limxaf(x)g(x)00 or 

then, it could be calculated as,

limxaf(x)g(x)=limxaf(x)g(x)=limxaf(x)g(x)=...=limxaf(n)(x)g(n)(x)

For example, sin(x)x, at x0.

4. Taylor Series

Approximate a function a certain point, by a series of terms.(detailing explaination sees Blog Section 6 )

We use the 1st, 2nd, 3rd, 4th, ... n^th derivatives, etc, to approximate the function at a certain value.

f(x)f(x0)+(xx0)f(x)|x=x0+12(xx0)f(x)|x=x0+...+1n!f(n)(x)|x=x0(xx0)n

For example, ex at x=0.

ex=1+x+x22!+x33!+...+xnn!

5. Integration

5.1 Intergration by Parts
y=u(x)v(x)y=uv+uvuv=yuv

and then integrate from both sides,

uvdx=ydxuvdx

as ydx=y+C, so we would get,

uvdx=vdu=yudv+C

For example,

xexdx=xdex=xexexdx+(C)=xexex+(C)
5.2 Reduction Formula

We define a integral, (In is called Gamma Function)

0ettndt=In

n is determined as the subscript of In, and could be treated as a constant in that integral.

We integrate that formula, and would get,

n0ettn1dt=InnIn1=In

If we keep doing that, we would get,

In=nIn1=n(n1)In2=...=n!I0

where,

I0=0etdt=1

so we get,

In=n!I0=n!
5.3 Other Tips
5.3.1 ln|f(x)|
f(x)f(x)=ln|x|+C

For example,

x1+x2dx=1211+x2dx2=1211+x2d(1+x2)=12ln|1+x2|+C
5.3.2 Decompose the Fraction - Factorisation

For example,

1(x2)(x+3)=Ax2+Bx+3A=15,B=15

The further implication is that.

Any rational expression f(x)g(x), ( with degree of f(x) < degree of g(x)), could be rewritten as.

f(x)g(x)F1+F2+...+Fk

, where each Fi Is,

Fi=A(px+q)morAx+B(px+q)m

6. Complex Number - i

6.1 Definition
z=x+iyi=i,i2=1

and z could be expressed in polar co-ordinate form as,

z=r(cosθ+i sinθ)

, where

x=r cosθ,y=r sinθ

The set of all complex numbers is denoted C; and for any complex number z, we could write zC. ( RC ).

6.2 Modulus

The modulus of z donates |z| is defined as,

|z|=r=x2+y2

6.3 Complex Conjugate
z¯=xiy

For example, if z=x+iy, then z¯=xiy.

6.4 Polar Form
z=r(cos θ+i sin θ)=reiθ

by Euler's Identity,

eiθ=cos θ+i sin θeiθ=cos θi sin θ|z|=r,arg z=θ
6.5 Euler's Fomula

The Euler's Identity is shown as, by applying Taylor's Expansion and by i2=1,

eiθ=1+iθ+(iθ)22!+...+(iθ)nn!=(1θ22+θ44!+...)+i×(θtheta33!+θ55!+...)=cos θ+i sin θ

Plug θ=π into Euler's Formula,

eiπ=cos π+sin πeiπ=1

7.Higher Dervatives

2fx2=fxx=x(fx)2fxy=fxy=y(fx),fxy=fyxsequence no matters if 2nd derivatives exist and continuous

By Fanyu Zhao